Question

Розв'яжить ривняня 2(x-5)-4(x+3)=x-43

Answer 1

$2\cdot\left(x-5\right)-4\cdot\left(x+3\right)=x-43\\-2x-22=x-43\\-2x-22-x=x-43-x\\-3x-22=x-43-x\\-3x-22=-43\\-3x-22+22=-43+22\\-3x=-43+22\\-3x=-21\\\frac{-3x}{-3}=\frac{-21}{-3}\\x=\frac{-21}{-3}\\x=7$

ответь:

$x=7$

Answer 2

Sure, let's solve the equation step by step:

$2(x-5) - 4(x+3) = x - 43$

First, distribute the numbers outside the parentheses:

$2x - 10 - 4x - 12 = x - 43$

Now, combine like terms on both sides of the equation:

$-2x - 22 = x - 43$

Add $2x$ to both sides to get the variable terms on one side:

$-22 = 3x - 43$

Now, add 43 to both sides to isolate the variable:

$21 = 3x$

Finally, divide by 3 to solve for $x$:

$x = 7$

So, the solution to the equation is $x = 7$.