Question

(2а-3)(2а+3)-4(а²+5)​

Answer 1

Ответ:

-29

Объяснение:

(2а-3)(2а+3)-4(а²+5)​ = (2a)²-3²-4a²-20 = 4a²-9-4a²-20 = -29

Для решения использована формула разности квадратов:

a²-b²=(a-b)(a+b)

Answer 2

Ответ:-29

Объяснение:

Answer 3

To simplify the expression (2a-3)(2a+3)-4(a^2+5), you can follow these steps:

1. First, apply the distributive property (FOIL) to the first term: (2a - 3)(2a + 3) = 2a * 2a + 2a * 3 - 3 * 2a - 3 * 3 = 4a^2 + 6a - 6a - 9

2. Notice that the middle terms (6a and -6a) will cancel each other out, leaving you with: 4a^2 - 9

3. Next, apply the distributive property to the second term: -4(a^2 + 5) = -4a^2 - 20

4. Now, subtract the second term from the first term: (4a^2 - 9) - (-4a^2 - 20)

To subtract the second term, you can distribute the negative sign: 4a^2 - 9 + 4a^2 + 20

5. Combine like terms: 4a^2 + 4a^2 - 9 + 20

6. Add the coefficients of like terms: 8a^2 + 11

So, the simplified expression is 8a^2 + 11.