Question

X+1/x-2 > 3/(x-2) - 1/2

Answer 1

Ответ:

как то так..............

Answer 2

To solve the inequality $\frac{x + 1}{x - 2} > \frac{3}{x - 2} - \frac{1}{2}$, you should start by finding a common denominator and simplifying the expression:

$\frac{x + 1}{x - 2} > \frac{3}{x - 2} - \frac{1}{2}$

First, note that both fractions have a common denominator of $x - 2$. So, we can combine them into a single fraction:

$\frac{x + 1 - \frac{1}{2}(x - 2)}{x - 2} > \frac{3}{x - 2}$

Now, you can simplify further:

$\frac{x + 1 - \frac{1}{2}x + 1}{x - 2} > \frac{3}{x - 2}$

Combine like terms in the numerator:

$\frac{\frac{1}{2}x + 2}{x - 2} > \frac{3}{x - 2}$

Now, you can see that both sides of the inequality have the same denominator (x - 2). You can eliminate this common denominator:

$\frac{1}{2}x + 2 > 3$

Now, isolate x:

$\frac{1}{2}x > 3 - 2$

$\frac{1}{2}x > 1$

Now, multiply both sides by 2 to solve for x:

$x > 2$

So, the solution to the inequality is $x > 2$.