Question

(4-y)(4+y)-2y(2y в квадрате-1)+4(y в кубе -4)

Answer 1

Ответ:

-y(y+2)

Объяснение:

16-y²-4y³-2y+4y³-16

-y²-2y

-y(y+2)

Answer 2

To simplify the given expression $(4-y)(4+y) - 2y(2y^2 - 1) + 4(y^3 - 4)$, let's expand and combine like terms:

1. Expand $(4-y)(4+y)$:

   $(4-y)(4+y) = 16 - y^2$

2. Expand $-2y(2y^2 - 1)$:

   $-2y(2y^2 - 1) = -4y^3 + 2y$

3. Expand $4(y^3 - 4)$:

   $4(y^3 - 4) = 4y^3 - 16$

Now substitute these back into the original expression and combine like terms:

$(16 - y^2) - 4y^3 + 2y + 4y^3 - 16$

Combine the $y^3$ terms:

$16 - y^2 + 2y - 16$

Combine the constant terms:

$-y^2 + 2y$

So, $(4-y)(4+y) - 2y(2y^2 - 1) + 4(y^3 - 4)$ simplifies to $-y^2 + 2y$.