Question

2x^2-x(2x-5)-2(2x-1)-5=0

Answer 1

Ответ:

х=3

Объяснение:

2х²-2x²+5x-4x+2-5=0

сокращаем 2x²-2x²

приводим подобные 5х-4х = х

получается х+2-5=0

х=5-2

х=3

Answer 2

To solve the quadratic equation 2x^2 - x(2x - 5) - 2(2x - 1) - 5 = 0, you can follow these steps:

1. First, distribute the terms on the right side of the equation: 2x^2 - 2x^2 + 5x - 4x + 2 - 5 = 0

2. Simplify the equation by combining like terms: (5x - 4x) + (2 - 5) = 0 x - 3 = 0

3. Now, isolate the variable x by adding 3 to both sides of the equation: x - 3 + 3 = 0 + 3 x = 3

So, the solution to the quadratic equation 2x^2 - x(2x - 5) - 2(2x - 1) - 5 = 0 is x = 3.