Question

14х – у = 30; 3) (11х + 10 y = 73,5, 6x - 5у = -54; ​

Answer 1

Ответ:

14х-у=30

14х-у-30=0

11х+10у=73,5(умножить все на 10)

22х+20у-147=0

6х-5у=-54

6х-5у+54=0

Answer 2

You've provided a system of linear equations:

1. 14x - y = 30
2. 11x + 10y = 73.5
3. 6x - 5y = -54

To solve this system of equations, you can use either the substitution method or the elimination method. I'll use the elimination method in this example:

First, let's multiply equation 1 by 10 to make the coefficients of y in equations 1 and 2 the same:

1. 140x - 10y = 300

Now, add equation 2 to the modified equation 1:

(140x - 10y) + (11x + 10y) = 300 + 73.5

Simplify:

151x = 373.5

Now, divide by 151 to solve for x:

x = 373.5 / 151 x ≈ 2.47 (rounded to two decimal places)

Now that we have found the value of x, we can substitute it back into one of the original equations to find the value of y. Let's use equation 1:

14x - y = 30 14(2.47) - y = 30

Now, solve for y:

34.58 - y = 30

Subtract 34.58 from both sides:

-y = 30 - 34.58 -y = -4.58

Finally, divide by -1 to solve for y:

y = 4.58

So, the solution to the system of equations is:

x ≈ 2.47 y ≈ 4.58