
Сколько воды нужно выпарить из 12 л 60%ого соляного раствора чтобы его концентрация стала равна 85?
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Ответ:вот
Объяснение:




Calculation of Water Evaporation from a Salt Solution
To determine the amount of water that needs to be evaporated from a 12 L 60% salt solution to achieve a concentration of 85%, we can use a table to track the changes in the solution's composition.
Let's break down the problem into steps:
Step 1: Initial Solution - Initial volume of the solution: 12 L - Initial concentration of the solution: 60% - Initial amount of salt in the solution: 12 L * 0.6 = 7.2 L
Step 2: Final Solution - Final concentration of the solution: 85%
Step 3: Calculation - Let's assume that x liters of water need to be evaporated from the initial solution. - The final volume of the solution will be (12 - x) L. - The final amount of salt in the solution will remain the same at 7.2 L.
Using the formula for concentration:
Concentration = Amount of solute / Volume of solution
We can set up the following equation:
0.85 = 7.2 L / (12 - x) L
To solve for x, we can cross-multiply and solve the equation:
0.85 * (12 - x) = 7.2
Simplifying the equation:
10.2 - 0.85x = 7.2
0.85x = 10.2 - 7.2
0.85x = 3
x = 3 / 0.85
x ≈ 3.53 L
Therefore, approximately 3.53 liters of water need to be evaporated from the initial 12 L 60% salt solution to achieve a concentration of 85%.
Table Representation
| Step | Volume of Solution (L) | Concentration (%) | Amount of Salt (L) | |------|-----------------------|--------------------|--------------------| | Initial Solution | 12 | 60% | 7.2 | | Final Solution | 12 - x | 85% | 7.2 |
Using the calculated value of x (approximately 3.53 L), we can fill in the table:
| Step | Volume of Solution (L) | Concentration (%) | Amount of Salt (L) | |------|-----------------------|--------------------|--------------------| | Initial Solution | 12 | 60% | 7.2 | | Final Solution | 12 - 3.53 ≈ 8.47 | 85% | 7.2 |
Please note that the values in the table are rounded for simplicity.
I hope this explanation helps! Let me know if you have any further questions.


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