Question

(6c-1)²-(2c-3)²=8(4c²-1) доказать личность​

Answer 1

Ответ:

(6c)²-2*6c*1+1²

36c²-12c+1

36с-12с+1-(4с²-12с+9)=32с²-8

36с-12с+1-4с²+12с-9=32с²-8

36c²+1-4c²-9=32c²-8

(36-4)c²=32c²

32c²+1-9=32c²-8

32с²-8=32с²-8

С принадлежит Ř.

Answer 2

(6c-1)²-(2c-3)²=8(4c²-1)

36c²-12c+1-(4с²-12с+9)=32с²-8

36c²-12c+1-4с²+12с-9=32с²-8

Сокращаем: 12с и -12с

Приводим подобные члены: 36c²-4c²

Вычисляем разность: 1-9=-8

В итоге получаем:

32с²-8=32с²-8

Answer 3

To solve the equation (6c-1)² - (2c-3)² = 8(4c²-1) and prove its identity, we can expand both sides of the equation and simplify.

Expanding and Simplifying the Equation

Let's start by expanding the equation on both sides:

(6c-1)² - (2c-3)² = 8(4c²-1)

Expanding the square terms, we get:

(36c² - 12c + 1) - (4c² - 12c + 9) = 32c² - 8

Simplifying further, we have:

36c² - 12c + 1 - 4c² + 12c - 9 = 32c² - 8

Combining like terms, we get:

32c² - 8 = 32c² - 8

Proving the Identity

As we can see, both sides of the equation are equal to 32c² - 8. Therefore, we have proved the identity.

In conclusion, the equation (6c-1)² - (2c-3)² = 8(4c²-1) is an identity, as both sides of the equation are equal to 32c² - 8.