Question

Find the value of x2x^2 + 5x + 40​

Answer 1

Ответ:

не имеет решений

Объяснение:

D=25-160=-135

Answer 2

To find the value of x in the equation x^2 + 5x + 40 = 0, we can use the quadratic formula.

The quadratic formula states that for an equation of the form ax^2 + bx + c = 0, the solutions for x can be found using the formula:

x = (-b ± √(b^2 - 4ac)) / (2a)

For the given equation x^2 + 5x + 40 = 0, we have: a = 1 b = 5 c = 40

Substituting these values into the quadratic formula, we get:

x = (-5 ± √(5^2 - 4 * 1 * 40)) / (2 * 1)

Simplifying further:

x = (-5 ± √(25 - 160)) / 2 x = (-5 ± √(-135)) / 2

Since the discriminant (b^2 - 4ac) is negative (-135), the equation does not have real solutions. The roots of this equation would be complex numbers.