Question

Запишите в виде произведения 4(а+1)²-1 помогите пожалуйста ​

Answer 1

$4(a+1)^2-1=(2(a+1)-1)\cdot(2(a+1)+1)=(2a+2-1)\cdot(2a+2+1)=(2a+1)\cdot(2a+3)$

Answer 2

Solution for 4(a+1)²-1:

To solve the expression 4(a+1)²-1, we can follow these steps:

1. Expand the expression: Expand the squared term using the formula (a+b)² = a² + 2ab + b². 2. Apply the multiplication: Multiply the expanded terms by 4 and subtract 1 at the end.

Let's proceed with the solution:

Step 1: Expand the expression

The expression 4(a+1)²-1 can be expanded as follows: 4(a+1)² = 4(a² + 2a + 1)

Step 2: Apply the multiplication and subtraction

Now, we multiply each term by 4 and subtract 1: 4(a+1)²-1 = 4a² + 8a + 4 - 1 4(a+1)²-1 = 4a² + 8a + 3

So, the expression 4(a+1)²-1 simplifies to 4a² + 8a + 3.

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