Question

) Реши задачу с помощью уравнения. Длина прямоугольника на 7 см больше ширины, а его площадь равна 60 см 2 . Найди стороны прямоугольника и его периметр. срочно помогите пожалуйста​

Answer 1

Ответ:

12 см;  5 см;  34 см.

Объяснение:

Пусть длина прямоугольника х см, тогда ширина х-7 см. По условию

х(х-7)=60

х²-7х-60=0

По теореме Виета х=-5 (не подходит)  х=12.

Длина прямоугольника 12 см, ширина 12-7=5 см.

Р=2(12+5)=34 см.

Answer 2

Problem Analysis

We are given that the length of a rectangle is 7 cm greater than its width, and the area of the rectangle is 60 cm^2. We need to find the dimensions of the rectangle and its perimeter.

Solution

Let's assume the width of the rectangle is x cm. According to the problem, the length of the rectangle is 7 cm greater than its width, so the length can be represented as x + 7 cm.

The area of a rectangle is given by the formula: Area = length × width. In this case, the area is given as 60 cm^2. We can set up the following equation:

(x + 7) × x = 60

To solve this equation, we can expand and rearrange it:

x^2 + 7x = 60

Now, let's solve this quadratic equation to find the value of x.

Solving the Equation

To solve the quadratic equation x^2 + 7x = 60, we can rearrange it to the standard form:

**x^2