Question

(a+b)(a²-ab+b²) =(a - b)(a²+ab+b²) =решите примеры, пожалуйста​

Answer 1

Ответ:

a^3 + b^3

a^3 - b^3

Объяснение:

Это из формул сокращенного умножения

(a+b)(a²-ab+b²)=a^3 + b^3

(a - b)(a²+ab+b²)=a^3 -b^3

Вывод

[

k(a+b)=ka + kb

(a+b)(d+c) =ad+ac+bd+cd

[(a+b)(d+c)=d(a+b)+c(a+b)=ad+ac+bd+cd]

]

(a+b)(a²-ab+b²)=a^3 -ba^2 +ab^2+ ba^2-ab^2+b^3=a^3+b^3

(a-b)(a²+ab+b²)=a^3 +ba^2 +ab^2- ba^2-ab^2-b^3=a^3-b^3

Answer 2

Solving the Equation

The given equation is: (a+b)(a²-ab+b²) = (a - b)(a²+ab+b²)

To solve this equation, we can use the formula for the difference of squares, which states that a² - b² = (a - b)(a + b).

Applying the Formula

We can apply the formula for the difference of squares to the expression a² - ab + b²: a² - ab + b² = (a - b)²

Now, let's substitute this back into the original equation: (a+b)(a²-ab+b²) = (a - b)(a²+ab+b²) = (a+b)(a - b)²

Conclusion

Therefore, the given equation simplifies to: (a+b)(a²-ab+b²) = (a - b)(a - b)²

This is the simplified form of the given equation.