Question

(2-х)(3-х)= (х+2)(х-5)

Answer 1

раскрываем скобки.

(2-х)(3-х)=(х+2)(х-5)

6-2х-3х+х²=х²-5х+2х-10

6-5х= -3х-10

-5х+3х= -10-16

-2х= -16

х= -16 : (-2)

х= 8

Answer 2

$(2-x)(3-x)=(x+2)(x-5)\\6-2x-3x+x^{2} =x^{2} -5x+2x-10\\x^{2}-x^{2}-5x+5x-2x+10+6=0\\-2x+16=0\\-2x=-16\\x=8$Ответ:

Объяснение:

Answer 3

To solve the equation (2-x)(3-x) = (x+2)(x-5), we can expand both sides and simplify:

Expanding the left side: (2 - x)(3 - x) = 2(3 - x) - x(3 - x) = 6 - 2x - 3x + x^2 = x^2 - 5x + 6

Expanding the right side: (x + 2)(x - 5) = x(x - 5) + 2(x - 5) = x^2 - 5x + 2x - 10 = x^2 - 3x - 10

Now we have the equation x^2 - 5x + 6 = x^2 - 3x - 10.

Subtracting x^2 from both sides: -5x + 6 = -3x - 10

Adding 3x to both sides: -2x + 6 = -10

Subtracting 6 from both sides: -2x = -16

Dividing by -2: x = 8

So the solution to the equation (2-x)(3-x) = (x+2)(x-5) is x = 8.