Question

2bx+abc+bcx+2ab розкласти на множники​

Answer 1

$2bx+abc+bcx+2ab=b\cdot(2x+ac+cx+2a)=b\cdot(x\cdot(2+c)+a\cdot(c+2))=b\cdot(2+c)\cdot(x+a)$

Answer 2

Factoring the Expression 2bx + abc + bcx + 2ab

To factor the expression 2bx + abc + bcx + 2ab, we can look for common factors among the terms and then factor them out.

First, let's identify any common factors among the terms.

The common factors among the terms are b and a. We can factor out these common factors to simplify the expression.

Factoring out the common factors, we get:

2bx + abc + bcx + 2ab = b(2x + ac) + c(bx + 2a)

So, the factored form of the expression 2bx + abc + bcx + 2ab is b(2x + ac) + c(bx + 2a).