Question

3c-2/3c+2=2c-5/2c+5 ​

Answer 1

Ответ:

Смотри решение на фото..

Answer 2

To solve the equation 3c - 2 / 3c + 2 = 2c - 5 / 2c + 5, we can start by cross-multiplying to eliminate the fractions.

Cross-multiplying means multiplying the numerator of the left side with the denominator of the right side, and vice versa. Then we equate the two resulting expressions.

(3c - 2) * (2c + 5) = (3c + 2) * (2c - 5)

Expanding both sides of the equation:

(3c * 2c) + (3c * 5) - (2 * 2c) - (2 * 5) = (3c * 2c) + (3c * -5) + (2 * 2c) - (2 * -5)

6c^2 + 15c - 4c - 10 = 6c^2 - 15c + 4c + 10

Combining like terms:

6c^2 + 11c - 10 = 6c^2 - 11c + 10

Next, we can eliminate the common terms on both sides by subtracting 6c^2 from both sides:

11c - 10 = -11c + 10

Now, let's isolate the variable terms on one side and the constant terms on the other side. We can do this by adding 11c to both sides:

11c - 11c - 10 = -11c + 11c + 10

Simplifying:

-10 = 10

Since -10 is not equal to 10, we have reached an inconsistency. Therefore, there is no solution to the given equation.