Question

Докажите тождество: а) -x(x-a)(x+b)=x(a-x)(b+x) б) (-а-b)(a+b) = -(a+b)²в) 36-(-(9c-15))=3(3c+7) г) y(-2-(y-4))=y(2-y)помогите пожалуйста ​ мне срочно нужно !!! ПОЖАЛУЙСТА

Answer 1

Ответ:

см фоьо

Объяснение:

Answer 2

a) Proof of Identity: -x(x-a)(x+b) = x(a-x)(b+x)

To prove the identity -x(x-a)(x+b) = x(a-x)(b+x), we can simplify both sides of the equation and show that they are equal.

Starting with the left-hand side (LHS):

LHS = -x(x-a)(x+b) = -x(x^2 + bx - ax - ab) = -x(x^2 + (b-a)x - ab)

Now, let's simplify the right-hand side (RHS):

RHS = x(a-x)(b+x) = x(ab + bx - ax - x^2) = x(ab + (b-a)x - x^2)

Comparing the LHS and RHS, we can see that they are equal:

LHS = -x(x^2 + (b-a)x - ab) = x(ab + (b-a)x - x^2) = RHS

Therefore, we have proved the identity -x(x-a)(x+b) = x(a-x)(b+x).

b) Proof of Identity: (-a-b)(a+b) = -(a+b)²

To prove the identity (-a-b)(a+b) = -(a+b)², we can simplify both sides of the equation and show that they are equal.

Starting with the left-hand side (LHS):

LHS = (-a-b)(a+b) = -a(a+b) - b(a+b) = -a² - ab - ab - b² = -a² - 2ab - b²

Now, let's simplify the right-hand side (RHS):

RHS = -(a+b)² = -(a+b)(a+b) = -a(a+b) - b(a+b) = -a² - ab - ab - b² = -a² - 2ab - b²

Comparing the LHS and RHS, we can see that they are equal:

LHS = -a² - 2ab - b² = RHS

Therefore, we have proved the identity (-a-b)(a+b) = -(a+b)².

c) Proof of Identity: 36 - (-(9c-15)) = 3(3c+7)

To prove the identity 36 - (-(9c-15)) = 3(3c+7), we can simplify both sides of the equation and show that they are equal.

Starting with the left-hand side (LHS):

LHS = 36 - (-(9c-15)) = 36 + (9c-15) = 36 + 9c - 15 = 9c + 21

Now, let's simplify the right-hand side (RHS):

RHS = 3(3c+7) = 9c + 21

Comparing the LHS and RHS, we can see that they are equal:

LHS = 9c + 21 = RHS

Therefore, we have proved the identity 36 - (-(9c-15)) = 3(3c+7).

d) Proof of Identity: y(-2-(y-4)) = y(2-y)

To prove the identity y(-2-(y-4)) = y(2-y), we can simplify both sides of the equation and show that they are equal.

Starting with the left-hand side (LHS):

LHS = y(-2-(y-4)) = y(-2-y+4) = y(-y+2) = -y^2 + 2y

Now, let's simplify the right-hand side (RHS):

RHS = y(2-y) = 2y - y^2

Comparing the LHS and RHS, we can see that they are equal:

LHS = -y^2 + 2y = RHS

Therefore, we have proved the identity y(-2-(y-4)) = y(2-y).

I hope this helps! Let me know if you have any further questions.