Question

3. Найдите 4cos2t/3 sin4t' если sin2t = 0,5 помогите пожалуйстааааа срочнооооооо

Answer 1

Объяснение:

$\frac{4*cos(2t)}{3*sin(4t)} =\frac{4*cos(2t)}{3*2*sin(2t)*(cos(2t)} =\frac{2}{3*sin(2t)}=\frac{2}{3*0,5}=\frac{2}{1,5}=\frac{2}{\frac{3}{2} } =\frac{2*2}{3}=\frac{4}{3} =1\frac{1}{3}.$

Answer 2

To find the value of the expression 4cos(2t)/3sin(4t') given that sin(2t) = 0.5, we can use trigonometric identities to simplify the expression and then substitute the given value.

Let's start by simplifying the expression 4cos(2t)/3sin(4t'). We can rewrite it as (4/3)(cos(2t)/sin(4t')).

Next, we can use the identity cos(2t) = 1 - 2sin^2(t) to rewrite the numerator. Substituting this identity, we get (4/3)(1 - 2sin^2(t))/sin(4t').

Now, let's use the identity sin(4t') = 2sin(2t')cos(2t') to rewrite the denominator. Substituting this identity, we get (4/3)(1 - 2sin^2(t))/(2sin(2t')cos(2t')).

Since we are given that sin(2t) = 0.5, we can substitute this value into the expression. This gives us (4/3)(1 - 2(0.5)^2)/(2sin(2t')cos(2t')).

Simplifying further, we have (4/3)(1 - 2(0.25))/(2sin(2t')cos(2t')).

Calculating the values inside the parentheses, we get (4/3)(1 - 0.5)/(2sin(2t')cos(2t')).

Simplifying the numerator, we have (4/3)(0.5)/(2sin(2t')cos(2t')).

Further simplifying, we get (2/3)/(2sin(2t')cos(2t')).

Finally, we can cancel out the common factor of 2 in the numerator and denominator, giving us the simplified expression 1/(3sin(2t')cos(2t')).

So, the value of the expression 4cos(2t)/3sin(4t') when sin(2t) = 0.5 is 1/(3sin(2t')cos(2t')).

Please note that I have simplified the expression based on the given information. If you have any specific values for t and t', please provide them so that I can calculate the exact value for you.