Question

Функція задана формулою у = - 3х + 1. Складіть таблицю значень функції для значень аргументу - 4; - 2; 0; 2; 4.

Answer 1

Ответ:

у=-3x+1

y(-4) = -3•(-4) +1

y(-4) =12+1

y(-4) =13

____________

y=-3x+1

y(-2)=-3•(-2) +1

y(-2) = 6+1

y(-2) = 7

____________

y=-3x+1

y(0) =-3•0+1

y(0) =0+1

y(0) =1

____________

y=-3x+1

y(2) = -3•2+1

y(2) = -6+1

y(2) =-5

____________

y=-3x+1

y(4) = -3•4+1

y(4) = -12+1

y(4) = -11

____________

Answer 2

Function Table for \( u = -3x + 1 \)

To create a table of values for the given function \( u = -3x + 1 \) for the specified input values, we can simply substitute each input value into the function and calculate the corresponding output value.

| \( x \) | \( u = -3x + 1 \) | | ------- | ----------------- | | -4 | \( -3(-4) + 1 = 12 + 1 = 13 \) | | -2 | \( -3(-2) + 1 = 6 + 1 = 7 \) | | 0 | \( -3(0) + 1 = 0 + 1 = 1 \) | | 2 | \( -3(2) + 1 = -6 + 1 = -5 \) | | 4 | \( -3(4) + 1 = -12 + 1 = -11 \) |

So, the table of values for the function \( u = -3x + 1 \) for the given input values is as follows:

| \( x \) | \( u = -3x + 1 \) | | ------- | ----------------- | | -4 | 13 | | -2 | 7 | | 0 | 1 | | 2 | -5 | | 4 | -11 |

This table represents the output values of the function for the specified input values.