Question

1) √x=52) √x+3=-33) √2-3x - 2=0

Answer 1

1)√х=5

х=25

2)√х+3=3

√х=00

х=0

3)√2-3х-2=0

х=(√2-2)/2

Answer 2

Let's solve each equation step by step:

1. √x = 5

To solve for x, we need to square both sides of the equation:

(√x)^2 = 5^2 x = 25

So the solution to the equation is x = 25.

2. √x + 3 = -3

To solve for x, we need to isolate the square root term:

√x = -3 - 3 √x = -6

Next, we square both sides of the equation:

(√x)^2 = (-6)^2 x = 36

So the solution to the equation is x = 36.

3. √(2 - 3x) - 2 = 0

To solve for x, we need to isolate the square root term and then square both sides of the equation:

√(2 - 3x) = 2

Squaring both sides:

(√(2 - 3x))^2 = 2^2 2 - 3x = 4

Now, we solve for x:

-3x = 4 - 2 -3x = 2 x = 2/(-3) x = -2/3

So the solution to the equation is x = -2/3.