Question

(6х²-3)+7х(6х²-3)-4у(6х²-3)​

Answer 1

Объяснение:

(6х²-3)+7х(6х²-3)-4у(6х²-3)=(6х²-3)*1+(6х²-3)*7х+(6х²-3)*(-4у)=

(6х²-3)*(1+7х+(-4у))=(6х²-3)*(1+7х-4у) =(3*2х²-3*1)*(1+7х-4у)

=3(2х²-1)*(1+7х-4у)

Answer 2

To simplify the expression (6x² - 3) + 7x(6x² - 3) - 4y(6x² - 3), we can distribute the coefficients:

First, distribute the coefficient 7x: 7x(6x² - 3) = 42x³ - 21x

Next, distribute the coefficient -4y: -4y(6x² - 3) = -24xy + 12y

Now, the expression becomes: (6x² - 3) + (42x³ - 21x) - (24xy + 12y)

Combining like terms, we have: 6x² + 42x³ - 3 - 21x - 24xy - 12y

This can be further simplified by rearranging the terms: 42x³ + 6x² - 21x - 24xy - 12y - 3

So, the simplified form of the expression (6x² - 3) + 7x(6x² - 3) - 4y(6x² - 3) is 42x³ + 6x² - 21x - 24xy - 12y - 3.