Question

(2x − 3)(2x + 3) - (x − 2)(x + 1) = 7​

Answer 1

Ответ:

решение смотри на фотографии

Answer 2

To solve the given equation:

(2x - 3)(2x + 3) - (x - 2)(x + 1) = 7

Let's simplify it step by step:

Expanding the expressions within the parentheses:

(4x^2 - 9) - (x^2 - x - 2) = 7

Remove the parentheses:

4x^2 - 9 - x^2 + x + 2 = 7

Combine like terms:

3x^2 + x - 7 = 7

Rearrange the equation to bring it to standard quadratic form:

3x^2 + x - 7 - 7 = 0

3x^2 + x - 14 = 0

Now, you can either factor this quadratic equation or use the quadratic formula to find the solutions. Let's use the quadratic formula:

x = (-b ± √(b^2 - 4ac)) / (2a)

For our equation, a = 3, b = 1, and c = -14. Plugging in these values, we get:

x = (-1 ± √(1^2 - 4(3)(-14))) / (2(3))

Simplifying further:

x = (-1 ± √(1 + 168)) / 6

x = (-1 ± √169) / 6

x = (-1 ± 13) / 6

We have two possible solutions:

x1 = (-1 + 13) / 6 = 12 / 6 = 2 x2 = (-1 - 13) / 6 = -14 / 6 = -7/3

Therefore, the solutions to the equation are x = 2 and x = -7/3.