Question

|2х-1|+7=8пжжжжжжжжжж​

Answer 1

Ответ:

|2x-1|=8-7|2x-1|=12x-1=1        

2x-1=-12x=2                                

2x=0

x=1                                  

x=0

Объяснение:

Answer 2

Ответ:

|2x-1|=8-7|2x-1|=12x-1=1

2x-1=-12x=2

2x=0

x=1

x=0

Answer 3

To solve the equation |2x - 1| + 7 = 8, we need to isolate the absolute value term and then solve for x. Let's break it down step by step:

|2x - 1| + 7 = 8

Subtract 7 from both sides:

|2x - 1| = 1

Now we have two cases to consider, one for when the expression inside the absolute value is positive and another for when it is negative.

Case 1: 2x - 1 > 0

If 2x - 1 is greater than zero, the absolute value is unnecessary, and we can remove the absolute value bars without changing the inequality. So we have:

2x - 1 = 1

Add 1 to both sides:

2x = 2

Divide both sides by 2:

x = 1

Case 2: 2x - 1 < 0

If 2x - 1 is less than zero, the expression inside the absolute value becomes its negation when we remove the absolute value bars. So we have:

-(2x - 1) = 1

Distribute the negative sign:

-2x + 1 = 1

Subtract 1 from both sides:

-2x = 0

Divide both sides by -2:

x = 0

Therefore, the solution to the equation |2x - 1| + 7 = 8 is x = 1 and x = 0.