Question

12 – (3х² + 5х) + (–7х + 3х²) = 0

Answer 1

$\displaystyle\bf\\12-\Big(3x^{2} +5x\Big)+\Big(-7x+3x^{2}\Big )=0\\\\12-3x^{2} -5x-7x+3x^{2} =0\\\\\Big(\underbrace{-3x^{2} +3x^{2}}_{0} \Big)-\Big(\underbrace{5x+7x}_{12x}\Big)+12=0\\\\-12x+12=0\\\\-12x=-12\\\\\boxed{x=1}$

Answer 2

12-3х(2)-5х-7х+3х(2)=0
12-12х=0
-12х=-12
х=1

Answer 3

To solve the equation 12 - (3x² + 5x) + (-7x + 3x²) = 0, we can simplify and combine like terms:

12 - 3x² - 5x - 7x + 3x² = 0

Next, we can combine the x² terms and the x terms:

(-3x² + 3x²) + (-5x - 7x) + 12 = 0

0 + (-12x) + 12 = 0

Now, we can simplify further:

-12x + 12 = 0

To isolate x, we can subtract 12 from both sides:

-12x = -12

Finally, we can solve for x by dividing both sides by -12:

x = (-12) / (-12)

x = 1

Therefore, the solution to the equation 12 - (3x² + 5x) + (-7x + 3x²) = 0 is x = 1.