Question

Даю 40 баллов решите быстрее 492. Винесіть за дужки спільний множник: 1) m²n + mn + n; 2) 3x6 +6x5-15¹; 3) 7a¹b³-14 + 21 4) 20b6c5-45b5c6-30b5c5.​

Answer 1

Вот брала удачи!!!!!!!!!!!!!!

Answer 2

1. m²n + mn + n

To factor out the common factor, we observe that each term in the expression has an 'n' as a factor. Thus, we can factor out 'n' from each term:

n(m² + m + 1)

So the expression factored with the common factor 'n' is n(m² + m + 1).

2. 3x6 + 6x5 - 15¹

In this expression, we can factor out a common factor of '3' from each term:

3(x6 + 2x5 - 5¹)

So the expression factored with the common factor '3' is 3(x6 + 2x5 - 5¹).

3. 7a¹b³ - 14 + 21

In this expression, there are two terms that do not share any common factors. Therefore, we cannot factor out a common factor.

4. 20b6c5 - 45b5c6 - 30b5c5

To factor out the common factor, we observe that each term has 'b5c5' as a common factor. Thus, we can factor it out:

b5c5(20b + 45c - 30)

So the expression factored with the common factor 'b5c5' is b5c5(20b + 45c - 30).