Question

√11*3(в 6 степени)* √11*2²= √2⁴*3²*5⁴= √2(в 6 степени) *3⁴*5²=

Answer 1

$1)\sqrt{11*3^{6}}*\sqrt{11*2^{2}}=\sqrt{11*3^{6} *11*2^{2}}=\sqrt{2^{2}*(3^{3})^{2}*11^{2}}=2*3^{3} *11=22*27=594\\\\\\2)\sqrt{2^{4}*3^{2}*5^{4}}=\sqrt{(2^{2})^{2}*3^{2}*(5^{2})^{2}}=2^{2}*3*5^{2}=4*3*25=300\\\\\\3)\sqrt{2^{6}*3^{4}*5^{2}}=\sqrt{(2^{3})^{2}*(3^{2})^{2}*5^{2}}=2^{3}*3^{2}*5=8*9*5=360$

Answer 2

Решение во вложении, ответ подчёркнут двумя линиями

Answer 3

To simplify the expression, let's break it down step by step:

√11 * 3^6 * √11 * 2^2

First, let's simplify the terms within the square roots:

√11 * √11 = √(11 * 11) = √121 = 11

Now we have:

11 * 3^6 * 11 * 2^2

Next, let's simplify the exponential terms:

3^6 = 3 * 3 * 3 * 3 * 3 * 3 = 729

2^2 = 2 * 2 = 4

Now we have:

11 * 729 * 11 * 4

Let's multiply the numbers together:

11 * 729 * 11 * 4 = 359,856

So the simplified expression is:

√11 * 3^6 * √11 * 2^2 = 359,856