Question

(a+1)^2+6-(a^2-3)/ 2(a^2-1)

Answer 1

A^2+2a+1+6-a^2+3/2a^2-2=5+2a+1.5a^2
все умножаем на 2
3a^2+2a+10=0
a=-1.5
или a=3.33333333333...

Answer 2

To simplify the expression, we can first expand the numerator of the first term using the formula (a+b)^2 = a^2 + 2ab + b^2. Then, we can simplify the second term by finding a common denominator with the third term. Finally, we can simplify the resulting expression by canceling out common factors.

Here are the steps in detail:

(a+1)^2 = a^2 + 2a + 1

(a^2-3)/2(a^2-1) = (a^2-1-2)/2(a^2-1) = (a^2-1)/2(a^2-1) - 1/(a^2-1) = 1/2 - 1/(a^2-1)

Therefore, the expression becomes:

(a+1)^2 + 6 - (a^2-3)/2(a^2-1) = (a^2 + 2a + 1) + 6 - (1/2 - 1/(a^2-1))

= a^2 + 2a + 1 + 6 + 1/2 - 1/(a^2-1)

= a^2 + 2a + 7/2 - 1/(a^2-1)

This is the simplified form of the expression.