Question

+  = 

Answer 1

1\х +1\(х+1) - (х²-2)\ х(х+1) = 0
(х+1+х-х²+2) \ х (х+1) = 0
ОДЗ: х(х+1)≠0
х≠0
х≠-1
знаменатель можно опустить
2х+3-х²=0  /  * -1
х²-2х-3=0 ⇒ по теореме Виета: х₁+х₂= 2 , х₁*х₂ = -3 ⇒ х₁=3 х₂=-1 ∉ по ОДЗ
ответ: 3

Answer 2

I'm sorry, but your input is incomplete. Could you please provide more context or information so that I can better understand your request and provide an appropriate response?