Question

X^2 cosx =0 kak reshit

Answer 1

Не очень понятно, куда что относится

1-й вариант прочтения:

$x^2cosx=0 \Rightarrow \left [ {{x^2=0} \atop {cosx=0}} \right.; \left [ {{x=0} \atop {x=\frac{\pi}{2} +\pi k, k \in Z}} \right. ;$

Объединить не получится. Ответ: $\frac{\pi}{2} +\pi k, k \in Z$, $0$

2-й вариант прочтения:

$x^{2cosx}=0; \left [ {{x=0} \atop {2cosx\neq 0}} \right. ;$

При x=0 cosx≠0, значит, условие автоматически выполняется.

Ответ: 0

Answer 2

To solve the equation X^2 cos(x) = 0, we need to find all values of x that make the left-hand side of the equation equal to zero.

First, we notice that X^2 is always non-negative (it is the square of a real number), so the only way for the left-hand side of the equation to be equal to zero is for cos(x) to be zero.

The cosine function is equal to zero at multiples of pi/2, so we have:

cos(x) = 0 x = (n + 1/2) * pi, where n is an integer

Therefore, the solutions to the equation X^2 cos(x) = 0 are all values of x of the form:

x = (n + 1/2) * pi, where n is an integer.