Question

Решить иррациональное уравнение √=7 3√x=-3 √x=-2 √x-2=5

Answer 1

$1)\; \; \sqrt{x}=7\; \; \to \; \; \underline {x=49}\\\\2)\; \; 3\sqrt{x}=-3\; \to \; \sqrt{x}=-1$

Answer 2

task/29446256                                                                                                   =============

√x = 7 ⇔ x =7² = 49.

3√x = - 3 ⇔ √x = - 1  ⇒ x ∈ ∅ ,,   т.к, √x ≥ 0 .

√x = - 2  ⇒  x ∈ ∅ ,,   т.к, √x ≥ 0 .

√ ( x-2 ) = 5 ⇔ x - 2 = 5³ ⇔ x =27 .

Answer 3

1. √7 = 3√x - 3 To isolate the radical, we add 3 to both sides and then square both sides to get: √7 + 3 = 3√x (√7 + 3)^2 = 9x 7 + 6√7 + 9 = 9x 16 + 6√7 = 9x x = (16 + 6√7)/9

2. √x = -2 Since x must be non-negative for the square root to be defined, there are no solutions to this equation.

3. √x-2 = 5 Adding 2 to both sides, we get: √x = 7 Squaring both sides, we get: x = 49

Therefore, the only solution to the system of equations is x = 49.