Question

T^2+4t-1 ------------ (это типо дробь) t^2-36

Answer 1

T^2+4t-1/t^2-36=(t-1)^2/(t-6)(t+6)

какое само условие?
что нужно сделать?

Answer 2

It looks like you have a rational function, which is a fraction with polynomials in both the numerator and denominator. To simplify the expression, we can factor both the numerator and denominator and cancel out any common factors.

Starting with the numerator, we can use the quadratic formula to find the roots of the quadratic polynomial T^2 + 4T - 1:

T = (-b ± sqrt(b^2 - 4ac)) / 2a

Plugging in a = 1, b = 4, and c = -1, we get:

T = (-4 ± sqrt(16 + 4))/2 = (-4 ± sqrt(20))/2 = -2 ± sqrt(5)

So we have:

T^2 + 4T - 1 = (T - (-2 + sqrt(5))) * (T - (-2 - sqrt(5)))

Moving on to the denominator, we can factor it as the difference of two squares:

T^2 - 36 = (T - 6) * (T + 6)

Putting it all together, we get:

(T^2 + 4T - 1) / (T^2 - 36) = ((T - (-2 + sqrt(5))) * (T - (-2 - sqrt(5)))) / ((T - 6) * (T + 6))

This expression is already fully factored and cannot be further simplified.