Question

1) (x-8)^2-2x(6-x)^2 2) (c+7)c-(1-c)^23) 2(a-b)^2 4) a(1+2a)^2 5) -6(2x-y)^2 6) -y(3x-y)^2 Срочно нужно !!!

Answer 1

Ваще решение готово:

Answer 2

1) (x-8)(x-8)-2x(6-x)(6-x)=x²-16x+64-2x(36-12x+x²)=x²-16x+64-72x+24x²-2x³=25x²-88x+64-2x³
2) (c+7)c-(1-c)(1-c)=c²+7c-1+2c-c²=9c-1
3) 2(a-b)(a-b)=2(a²-2ab+b²)=2a²-4ab+2b²
4) a(1+2a)(1+2a)=a(1+4a+4a²)=a+4a²+4a³
5) -6(2x-y)(2x-y)=-6(4x²-4xy+y²)=-24x²+24xy-6y²
6) -y(3x-y)(3x-y)=-y(9x²-6xy+y²)=-9yx²+6y²x-y³

Answer 3

1. (x-8)^2-2x(6-x)^2

Expanding the second term using the identity (a-b)^2 = a^2 - 2ab + b^2, we get:

(x-8)^2 - 2x((6)^2 - 2(6)(x) + x^2) = (x-8)^2 - 2x(36 - 12x + x^2) = (x-8)^2 - 72x + 24x^2 - 2x^3

2. (c+7)c - (1-c)^2

Expanding the second term using the identity (a-b)^2 = a^2 - 2ab + b^2, we get:

(c+7)c - (1-c)^2 = c^2 + 7c - (1 - 2c + c^2) = c^2 + 7c - 1 + 2c - c^2 = 9c - 1

3. 2(a-b)^2

Expanding using the identity (a-b)^2 = a^2 - 2ab + b^2, we get:

2(a-b)^2 = 2(a^2 - 2ab + b^2) = 2a^2 - 4ab + 2b^2

4. a(1+2a)^2

Expanding using the identity (a+b)^2 = a^2 + 2ab + b^2, we get:

a(1+2a)^2 = a(1^2 + 2(1)(2a) + (2a)^2) = a(1 + 4a + 4a^2) = a + 4a^2 + 4a^3

5. -6(2x-y)^2

Expanding using the identity (a-b)^2 = a^2 - 2ab + b^2, we get:

-6(2x-y)^2 = -6(4x^2 - 4xy + y^2) = -24x^2 + 24xy - 6y^2

6. -y(3x-y)^2

Expanding using the identity (a-b)^2 = a^2 - 2ab + b^2, we get:

-y(3x-y)^2 = -y(9x^2 - 6xy + y^2) = -9x^2y + 6xy^2 - y^3