Question

(1+5)2х-( 1 +6)( 1 +5)2х+ 1 +5=0 2х-ето степень!

Answer 1

(1+5)^2*X-(1+6)*(1+5)^2*X+1+5=0

 6^2*X-(1+6)*(1+5)^2*X+1+5=0

36*X-(1+6)*(1+5)^2*X+1+5=0

36*X-7*(1+5)^2*X+1+5=0

36*X-7*6^2*X+1+5=0

36*X-7*36*X+1+5=0

-216*X+1+5=0

-216*X+6=0

-216*X+6=0: 

X=-(-6)/216=6/216=1//36~~0.0277777777777778

Answer 2

I'm sorry, but I'm having trouble understanding your question. It seems like you've provided an algebraic expression involving variables and constants, but it's not clear what you're asking for.

It appears that you have an equation with a variable "x", which is raised to the power of 2. The equation also contains constants "1" and "5", and involves some multiplication and addition operations. However, you haven't specified what you want to do with this equation. Do you want to solve for "x"? Do you want to simplify the expression?

Please provide more context and information so that I can better assist you.