Question

4(x-4)(x+8)=(3x+2)(x-5)+(x-1)(x+1)

Answer 1

Задание решено!!!ответ с подробным решением во вложении!!!
Отметь как лучший ответ!!

Answer 2

Let's start by simplifying both sides of the equation:

4(x-4)(x+8) = (3x+2)(x-5) + (x-1)(x+1)

Expanding the terms on the left side:

4(x^2 + 4x - 32) = (3x^2 - 13x - 10) + (x^2 - 1)

Simplifying the right side by combining like terms:

4x^2 + 16x - 128 = 4x^2 - 13x^2 - 13x - 10 + x^2 - 1

Simplifying the right side further by combining like terms:

4x^2 + 16x - 128 = -9x^2 - 12x - 11

Moving all terms to one side of the equation:

13x^2 + 28x - 117 = 0

Now we can solve for x using the quadratic formula:

x = (-b ± sqrt(b^2 - 4ac)) / 2a

where a = 13, b = 28, and c = -117

x = (-28 ± sqrt(28^2 - 4(13)(-117))) / 2(13)

x = (-28 ± sqrt(2116 + 6084)) / 26

x = (-28 ± sqrt(8200)) / 26

x = (-28 ± 20sqrt(2)) / 13

Therefore, the solutions to the equation are:

x ≈ -4.75 or x ≈ 2.32