Answer 1

$a^2 \sqrt[3]{a^5}/ \sqrt{a^3} \sqrt[4]{a^2} }=a^{2+5/3}/a^{3+1/2}=a^{9/3-7/2}=a^{-1/3}=1/ \sqrt[3]{a}$ [/tex]

Answer 2

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Answer 3

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Answer 4

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