Question

10x2+19x-2=10(x-0,1)(x+2)

Answer 1

Вот решение. Удачи :)

Answer 2

To verify the given equation, let's simplify both sides and check if they are equal:

Starting with the left-hand side (LHS):

10x^2 + 19x - 2

Now let's simplify the right-hand side (RHS):

10(x - 0.1)(x + 2)

Using the distributive property, we expand the expression inside the brackets:

10(x^2 + 2x - 0.1x - 0.2)

Simplifying further:

10(x^2 + 1.9x - 0.2)

Now, distribute the 10 across the terms inside the brackets:

10x^2 + 19x - 2

We can see that the simplified RHS expression is equal to the original LHS expression. Therefore, the equation 10x^2 + 19x - 2 = 10(x - 0.1)(x + 2) is true.