Question

1) (4x-1,6)(8+x)=0 2) x(5-0,2x)=0 3) (3x-2)(4+1/3x)=0 4) (2x+1,2)(x+1)(0,7x-0<21)=0

Answer 1

1 ) 4x-1,6 = 0
     4x=1.6 + 0
     4x = 1.6
      x =0.4 или 8+х=0
                      х=0-8
                      х=-8
Ответ : х = 0.4 или х=-8

Answer 2

Let's solve each equation step by step:

1. (4x-1)(8+x) = 0

To find the solutions, we set each factor equal to zero and solve for x:

4x - 1 = 0 or 8 + x = 0

Solving the first equation: 4x = 1 x = 1/4

Solving the second equation: 8 + x = 0 x = -8

Therefore, the solutions are x = 1/4 and x = -8.

2. x(5 - 0.2x) = 0

Again, we set each factor equal to zero and solve for x:

x = 0 or 5 - 0.2x = 0

Solving the second equation: 5 - 0.2x = 0 0.2x = 5 x = 5/0.2 x = 25

The solutions are x = 0 and x = 25.

3. (3x-2)(4 + (1/3)x) = 0

Setting each factor equal to zero:

3x - 2 = 0 or 4 + (1/3)x = 0

Solving the first equation: 3x = 2 x = 2/3

Solving the second equation: (1/3)x = -4 x = -4/(1/3) x = -4 * (3/1) x = -12

The solutions are x = 2/3 and x = -12.

4. (2x + 1.2)(x + 1)(0.7x - 0.21) = 0

Setting each factor equal to zero:

2x + 1.2 = 0 or x + 1 = 0 or 0.7x - 0.21 = 0

Solving the first equation: 2x = -1.2 x = -1.2/2 x = -0.6

Solving the second equation: x = -1

Solving the third equation: 0.7x = 0.21 x = 0.21/0.7 x = 0.3

The solutions are x = -0.6, x = -1, and x = 0.3.

Please note that the decimal values in the equations have been rounded for simplicity.