Question

1)2x+15x+5=0 2)4x^2+3x-2=0

Answer 1

2) D=9-4*4*(-2)=9+32=41
Ты походу неверно дал условие, так как из 41 не извлекается.

Answer 2

1) уточни
А все же если 2x²+15x+5=0
a=2; b=15; c=5
D=15²-4*2*5=225-40=185
x(1,2)=-15 ±√185 / 2*2
x1=-15-√185 / 4
x2=-15+√185 / 4
Если 2x+15x+5=0
17x+5=0
17x=-5
x=-5/17


2) 4x²-3x-2=0
a=4; b=-3; c=-2
D=(-3)²-4*4*(-2)=9+36=41
x(1,2)=3 ±√41 / 4*2
x1=3-√41 / 8
x2=3+√41 /8

Answer 3

Let's solve the equations one by one:

1. 2x + 15x + 5 = 0

Combining like terms, we have: 17x + 5 = 0

Subtracting 5 from both sides, we get: 17x = -5

Dividing both sides by 17, we have: x = -5/17

Therefore, the solution to the equation 2x + 15x + 5 = 0 is x = -5/17.

2. 4x^2 + 3x - 2 = 0

To solve this quadratic equation, we can use the quadratic formula, which states that for an equation of the form ax^2 + bx + c = 0, the solutions are given by:

x = (-b ± √(b^2 - 4ac)) / (2a)

For our equation 4x^2 + 3x - 2 = 0, we have: a = 4, b = 3, c = -2

Substituting these values into the quadratic formula, we get:

x = (-3 ± √(3^2 - 4 * 4 * -2)) / (2 * 4)

Simplifying further:

x = (-3 ± √(9 + 32)) / 8 x = (-3 ± √41) / 8

Therefore, the solutions to the equation 4x^2 + 3x - 2 = 0 are: x = (-3 + √41) / 8 x = (-3 - √41) / 8