Question

4ad+3(d-1) в квадрате

Answer 1

4ad+3(d-1) в квадрате $\\ 4ad+3(d-1)^{2} =4ad+3( d^{2}-2d+1)=4ad+3 d^{2} -6d+3$

Answer 2

To square the expression 4ad + 3(d - 1), we need to multiply the expression by itself:

(4ad + 3(d - 1))^2

To simplify this expression, we can expand it using the FOIL method (First, Outer, Inner, Last) and then combine like terms:

(4ad + 3(d - 1))^2 = (4ad)^2 + 2(4ad)(3(d - 1)) + (3(d - 1))^2 = 16a^2d^2 + 2(4ad)(3d - 3) + 9(d - 1)^2 = 16a^2d^2 + 2(12ad^2 - 12ad) + 9(d^2 - 2d + 1) = 16a^2d^2 + 24ad^3 - 24ad + 9d^2 - 18d + 9 = 16a^2d^2 + 24ad^3 + 9d^2 - 24ad - 18d + 9

So, (4ad + 3(d - 1))^2 simplifies to 16a^2d^2 + 24ad^3 + 9d^2 - 24ad - 18d + 9.