Question

1)(p+8)2= 2)(10x-3y)2= 3)(x-9)(x+9)= 4)(4m+7n)(7n-4m)

Answer 1

1)(p+8)2=p^2+16p+4

2)(10x-3y)2=100x^-60xy+9y^2

3)(x-9)(x+9)=x^2-81

4)(4m+7n)(7n-4m)=49n^2-16m^2

Answer 2

Let's solve each of the equations step by step:

1. (p + 8)^2: Expanding the equation using the square of a binomial formula, we have: (p + 8)^2 = p^2 + 2p(8) + 8^2 = p^2 + 16p + 64

2. (10x - 3y)^2: Expanding the equation using the square of a binomial formula, we have: (10x - 3y)^2 = (10x)^2 - 2(10x)(3y) + (3y)^2 = 100x^2 - 60xy + 9y^2

3. (x - 9)(x + 9): Expanding the equation using the difference of squares formula, we have: (x - 9)(x + 9) = x^2 - (9)^2 = x^2 - 81

4. (4m + 7n)(7n - 4m): Expanding the equation using the difference of squares formula, we have: (4m + 7n)(7n - 4m) = (4m)^2 - (7n)^2 = 16m^2 - 49n^2

So, the expanded forms of the given expressions are:

1. (p + 8)^2 = p^2 + 16p + 64
2. (10x - 3y)^2 = 100x^2 - 60xy + 9y^2
3. (x - 9)(x + 9) = x^2 - 81
4. (4m + 7n)(7n - 4m) = 16m^2 - 49n^2