Question

Sin^2b-sin^2b*cos^2b

Answer 1

sin²b-sin²b*cos²b=sin²b(1-cos²b)=sin²b*sin²b=sin⁴b

Answer 2

Ответ:

sin(b)^{4}

Объяснение:

sin(b)^{2} - sin(b)^{2} * cos(b)^{2}

sin(b)^{2} * (1 - cos(b)^{2})

sin(b)^{2} * sin(b)^{2}

sin(b)^{4}

Answer 3

Let's simplify the expression step by step.

The given expression is: sin^2(b) - sin^2(b) * cos^2(b)

We can factor out sin^2(b) from both terms: sin^2(b) * (1 - cos^2(b))

Now, we can use the trigonometric identity: sin^2(b) + cos^2(b) = 1 This identity can be rearranged as: sin^2(b) = 1 - cos^2(b)

Substituting this into our expression, we get: (1 - cos^2(b)) * (1 - cos^2(b))

Expanding the expression further, we have: (1 - cos^2(b))^2

This can be simplified using the formula for squaring a binomial: 1 - 2cos^2(b) + cos^4(b)

So, the simplified form of the expression sin^2(b) - sin^2(b) * cos^2(b) is 1 - 2cos^2(b) + cos^4(b).