Question

(х+9)(х-11)^2 (х-12) 0

Answer 1

1) d=36-36=0=>один корень x=6/2=3   (-бесконечности;3]2)d=144-144=0 x=12/2=6   (6;+беск.)

Answer 2

To solve the equation ${(x+9)(x-11)^2(x-12)}=0$, we set each factor equal to zero and solve for x:

Setting $x+9=0$, we subtract 9 from both sides: $x=-9$

Setting $(x-11)^2=0$, we take the square root of both sides: $x-11=0$ $x=11$

Setting $x-12=0$, we add 12 to both sides: $x=12$

Therefore, the solutions to the equation ${(x+9)(x-11)^2(x-12)}=0$ are $x=-9$, $x=11$, and $x=12$.