Question

4x^2 + 21x + 26 = 0.

Answer 1

$4x^2 + 21x + 26 = 0 \\ x= \frac{-21+- \sqrt{21^2-4*4*26} }{2*4} \\ x= \frac{-21+- \sqrt{441-416} }{8} \\ x= \frac{-21+- \sqrt{25} }{8} \\ x= \frac{-21+-5}{8} \\ \left[\begin{array}{ccc}x= \frac{-21+5}{8} \\ x=\frac{-21-5}{8} \end 1x=-2;- \frac{13}{4}$

Answer 2

To solve the quadratic equation 4x^2 + 21x + 26 = 0, we can use the quadratic formula:

x = (-b ± √(b^2 - 4ac)) / (2a)

In this equation, a = 4, b = 21, and c = 26. Substituting these values into the formula, we get:

x = (-(21) ± √((21)^2 - 4(4)(26))) / (2(4))

Simplifying further:

x = (-21 ± √(441 - 416)) / 8 x = (-21 ± √25) / 8 x = (-21 ± 5) / 8

This gives us two possible solutions:

x1 = (-21 + 5) / 8 x1 = -16 / 8 x1 = -2

x2 = (-21 - 5) / 8 x2 = -26 / 8 x2 = -13 / 4

Therefore, the solutions to the quadratic equation 4x^2 + 21x + 26 = 0 are x = -2 and x = -13/4.