Question

Решите пж, алгебра, 7 класс

Answer 1

1. a³b³ - 3³ = (ab - 3)(a²b² + 3ab +9)

2. a⁶ - m⁹ = (a²)³ - (m³)³ = (a² - m³)(a⁴ + a²m³ + m⁶)

3. 64a³ - 8b³ = (4a)³ - (2b)³ = (4a - 2b)(16a² + 8ab + 4b²)

4. 125 - x⁶y⁹ = 5³ - (x²y³)³ = (5 - x²y³)(25 + 5x²y³ + x⁴y⁶)

5. (2xy)³ - (3x)³ = (2xy - 3x)(4x²y² + 6x²y + 9x²)

6. 64 - x¹² = 4³ - (x⁴)³ = (4 - x⁴)(16 + 4x⁴ + x⁸)

7. a⁶ - 8b⁶ = (a²)³ - (2b²)³ = (a² - 2b²)(a⁴ + 2a²b² + 4b⁴)