Question

Тело массой 200 г брошено под углом 60 к горизонту со скоростью v0=8м.с. Определить импульс тела в верхней точке полета

Answer 1

Calculation of the Impulse of an Object at the Highest Point of its Flight

To determine the impulse of an object at the highest point of its flight, we need to consider the initial conditions of the object's motion. In this case, a body with a mass of 200 g is thrown at an angle of 60 degrees to the horizontal with an initial velocity of v0 = 8 m/s.

The impulse of an object is defined as the change in momentum it experiences. Momentum is the product of an object's mass and its velocity. Mathematically, impulse (J) is given by the equation:

J = Δp = m * Δv

where: - J is the impulse - Δp is the change in momentum - m is the mass of the object - Δv is the change in velocity

At the highest point of the object's flight, its vertical velocity component becomes zero. This means that the change in velocity (Δv) is equal to the initial vertical velocity (v0) since the final vertical velocity is zero.

Using the given values, we can calculate the impulse of the object at the highest point of its flight.

Step 1: Convert the mass from grams to kilograms: - Mass (m) = 200 g = 0.2 kg

Step 2: Calculate the change in velocity (Δv): - Δv = v0 = 8 m/s

Step 3: Calculate the impulse (J): - J = m * Δv = 0.2 kg * 8 m/s = 1.6 kg·m/s

Therefore, the impulse of the object at the highest point of its flight is 1.6 kg·m/s.