Question

Определите силу,с которой действует керосин (плотность керосина 800 кг/м3)на пробку площадью поперечного сечения 16 см2, если расстояние от пробки до уровня керосина 800мм. пожалуста помогите   

Answer 1

Calculation of the Force Exerted by Kerosene on the Cork

To determine the force exerted by kerosene on the cork, we can use the formula:

Force = Pressure x Area

First, let's calculate the pressure exerted by the kerosene on the cork. The pressure can be calculated using the formula:

Pressure = Density x g x h

Where: - Density is the density of kerosene (800 kg/m^3) - g is the acceleration due to gravity (9.8 m/s^2) - h is the height of the kerosene column above the cork (800 mm)

Converting the height from millimeters to meters, we have:

h = 800 mm = 0.8 m

Now, let's substitute the values into the formula to calculate the pressure:

Pressure = 800 kg/m^3 x 9.8 m/s^2 x 0.8 m

Using a calculator, we find that the pressure is approximately 6272 Pa (Pascals).

Next, we need to calculate the area of the cork. The area can be calculated using the formula:

Area = π x r^2

Where: - π is a mathematical constant approximately equal to 3.14159 - r is the radius of the cork (which can be calculated from the given cross-sectional area)

The given cross-sectional area is 16 cm^2. Converting this to square meters, we have:

Area = 16 cm^2 = 16 x 10^-4 m^2

Now, let's calculate the radius of the cork:

Area = π x r^2 16 x 10^-4 m^2 = 3.14159 x r^2

Solving for r, we find that the radius is approximately 0.071 m.

Finally, let's substitute the values into the formula to calculate the force:

Force = Pressure x Area Force = 6272 Pa x 0.071 m^2

Using a calculator, we find that the force exerted by the kerosene on the cork is approximately 445 N (Newtons).

Please note that the above calculation assumes that the kerosene is incompressible and that the pressure is evenly distributed across the cork's surface.