Question

рабочий с помощью подвижного блока с коэффициентом полезного действия равным 70 процентов равномерно поднимает груз массой 63 кг на 10 этаж строящегося дома.найти силу, с которой рабочий тянет за веревку, перекинутую через блок.ускорение свободного падения принять равным 10 H/кг. Спасибо

Answer 1

Calculation of the Force Exerted by the Worker

To find the force with which the worker pulls the rope, we can use the principle of work and energy. The work done by the worker is equal to the change in potential energy of the load.

The potential energy of an object is given by the formula:

Potential Energy = mass * acceleration due to gravity * height

In this case, the mass of the load is 63 kg and the height is equivalent to 10 floors. Since each floor is typically around 3 meters high, the total height is 10 * 3 = 30 meters.

The acceleration due to gravity is given as 10 m/s^2.

Using these values, we can calculate the potential energy of the load:

Potential Energy = 63 kg * 10 m/s^2 * 30 m = 18900 Joules

The work done by the worker is equal to the potential energy, so the work done is also 18900 Joules.

The work done is given by the formula:

Work = force * distance

In this case, the distance is the height of the building, which is 30 meters.

Therefore, we can rearrange the formula to solve for force:

Force = Work / Distance

Force = 18900 Joules / 30 meters

Calculating this, we find:

Force = 630 Newtons

Therefore, the force with which the worker pulls the rope, which is equivalent to the force exerted on the rope, is 630 Newtons.

Please note that the above calculation assumes ideal conditions and does not take into account any additional factors such as friction or the efficiency of the pulley system.