Question

Рыбак идет по берегу реки вверх по течению и тянет лодку с помощью веревки.Какой угол образует веревка с направлением перемещения лодки если известно что сила натяжения веревки Т=200 Н и работа совершенная рыбаком при перемещение лодки на s=8м равна a=1384 Дж

Answer 1

Дано   F=T=200 Н   A=1384 Н    S=8 м     a - ?
Работа в механике
A = F*S*cosa
cosa=A/F*S=1384/200*8=0,865
находим а по таблице
а=30 градусов

Answer 2

Finding the Angle between the Rope and the Direction of Boat Movement

To find the angle between the rope and the direction of boat movement, we can use the concept of work done. The work done by the fisherman in moving the boat is equal to the product of the force applied and the displacement of the boat. In this case, the force applied is the tension in the rope, and the displacement of the boat is given as 8 meters. The work done is given as 1384 Joules.

We can use the formula for work done: work = force x displacement x cos(theta), where theta is the angle between the force and the displacement.

Given that the tension in the rope is 200 N and the work done is 1384 J, we can rearrange the formula to solve for the angle theta:

1384 J = 200 N x 8 m x cos(theta)

Simplifying the equation:

cos(theta) = 1384 J / (200 N x 8 m)

cos(theta) = 0.865

To find the angle theta, we can take the inverse cosine (arccos) of 0.865:

theta = arccos(0.865)

Using a calculator, we find that the angle theta is approximately 30.6 degrees.

Therefore, the angle between the rope and the direction of boat movement is approximately 30.6 degrees.