Question

Тело массой 50 кг летит со скоростью 20 м/с и застряёт в песке на платформе массой 4 тонны которое движется в том же направлении что и тело со скоростью 1 м/с какова скорость платформы после падения тела

Answer 1

Проверь, но вроде это так решается

Answer 2

Calculation of the Platform's Velocity After the Object Falls

To calculate the velocity of the platform after the object falls into the sand, we can use the principle of conservation of momentum. According to this principle, the total momentum before the object falls is equal to the total momentum after the object falls.

The momentum of an object is given by the product of its mass and velocity. Let's denote the mass of the object as m_object and its velocity as v_object. Similarly, let's denote the mass of the platform as m_platform and its velocity as v_platform.

Before the object falls, the total momentum is the sum of the momentum of the object and the momentum of the platform:

Total momentum before = (m_object * v_object) + (m_platform * v_platform)

After the object falls, the total momentum is the sum of the momentum of the object (which becomes zero after it falls) and the momentum of the platform:

Total momentum after = 0 + (m_platform * v_platform_after)

Since the total momentum before and after must be equal, we can set up the following equation:

(m_object * v_object) + (m_platform * v_platform) = (m_platform * v_platform_after)

Plugging in the given values: - m_object = 50 kg (mass of the object) - v_object = 20 m/s (velocity of the object) - m_platform = 4,000 kg (mass of the platform) - v_object = 1 m/s (velocity of the platform before the object falls)

We can solve for v_platform_after.

Calculation:

(50 kg * 20 m/s) + (4,000 kg * 1 m/s) = (4,000 kg * v_platform_after)

Simplifying the equation:

1,000 kg * m/s + 4,000 kg * m/s = 4,000 kg * v_platform_after

5,000 kg * m/s = 4,000 kg * v_platform_after

Dividing both sides by 4,000 kg:

v_platform_after = (5,000 kg * m/s) / 4,000 kg

Simplifying the equation:

v_platform_after = 1.25 m/s

Answer:

The velocity of the platform after the object falls into the sand is 1.25 m/s.