Question

Санки скатились по склону горы длиной 48 м за 16с. Какова скорость санок в конце спуска? движение санок можно считать равноускоренным.

Answer 1

S=at²/2 
a = 2s/t² 
a=96/256
v=at=6 м/с (v=0.375*16 = 6 м/с)
Ответ: 6 м/с

Answer 2

$S= \frac{at^{2} }{2}=\frac{a16^{2} }{2}=48$
$a= \frac{2S}{ t^{2} }$
$V=at= \frac{2St}{t^{2}} = \frac{2S}{t} =2*48/16=6$м/с

Answer 3

Calculation of Speed

To calculate the speed of the sled at the end of the descent, we can use the equation for uniformly accelerated motion:

v = u + at

Where: - v is the final velocity (speed) of the sled - u is the initial velocity (speed) of the sled, which is assumed to be zero since the sled starts from rest - a is the acceleration of the sled - t is the time taken for the sled to travel down the slope

In this case, the sled travels a distance of 48 meters in 16 seconds. Since the motion is assumed to be uniformly accelerated, we can calculate the acceleration using the formula:

a = (2 * s) / (t^2)

Where: - s is the distance traveled by the sled - t is the time taken for the sled to travel the distance

Substituting the given values, we have:

a = (2 * 48) / (16^2) = 0.75 m/s^2

Now, we can calculate the final velocity using the equation:

v = u + at

Since the initial velocity is zero, the equation simplifies to:

v = at

Substituting the values, we have:

v = 0.75 * 16 = 12 m/s

Therefore, the speed of the sled at the end of the descent is 12 m/s.