Question

Автомобиль равномерно движется со скоростью V0 водитель тормозит и в течени T=2 с двигая равномерно за это время проходит путь 88 м кофциэнт трения = 0,6 лпределить начальную скорость V0

Answer 1

1)88:2*0,6=44*0,6=26,4м/с

Answer 2

Problem Analysis

We are given the following information: - The car is moving uniformly with an initial velocity V0. - The driver applies the brakes and decelerates uniformly for a time T = 2 s. - The car travels a distance of 88 m during this time. - The coefficient of friction is 0.6.

We need to determine the initial velocity V0 of the car.

Solution

To solve this problem, we can use the equations of motion for uniformly accelerated linear motion. The equation that relates the initial velocity (V0), final velocity (V), acceleration (a), and displacement (s) is:

V^2 = V0^2 + 2as

In this case, the car is decelerating, so the acceleration (a) is negative. The displacement (s) is given as 88 m.

Let's calculate the initial velocity V0 using this equation.

Calculation

Given: - Displacement (s) = 88 m - Coefficient of friction = 0.6 - Time (T) = 2 s

We need to find the initial velocity (V0).

Using the equation V^2 = V0^2 + 2as, we can rearrange it to solve for V0:

V0^2 = V^2 - 2as

Since the car is decelerating, the final velocity (V) is 0 m/s.

V0^2 = 0^2 - 2 * (-0.6) * 88

Simplifying the equation:

V0^2 = 2 * 0.6 * 88

V0^2 = 105.6

Taking the square root of both sides:

V0 = sqrt(105.6)

Calculating the value:

V0 ≈ 10.276 m/s

Therefore, the initial velocity of the car is approximately 10.276 m/s.

Answer

The initial velocity of the car is approximately 10.276 m/s.